BEEZYREVISOR

GCSE Physics Revision

Learn it. Recall it. Revise it.

GCSE Physics revision

Pressure in a fluid 2 (HT only)

Pressure in a fluid

AQA 4.5.5.1.2
Your specification

AQA student objectives

Learning pathway

All · Most · Some

ALL 🎯

Explain why, in a liquid, pressure at a point increases with the height of the column of liquid above that point and with the density of the liquid.

MOST 🎯🎯

Apply the scientific explanation of pressure in a fluid 2 to a relevant example.

SOME 🎯🎯🎯

Analyse a new situation involving pressure in a fluid 2 and explain the scientific reasoning.

Revision summary

Key knowledge

Read on screen, then print for Cornell-style active revision.

What Causes Pressure in a Liquid?

  • Pressure in a liquid is caused by the constant collisions of surrounding water molecules against a submerged object.
  • A component of the pressure is also due to the weight of the liquid above the object, acting as a downward force.
  • As an object moves deeper, the pressure increases because there is more liquid above it.

Factors Affecting Liquid Pressure

  • The depth of the object affects pressure — the greater the depth, the greater the pressure.
  • The density of the liquid affects pressure — a denser liquid has greater mass per unit volume, so a greater weight.
  • The gravitational field strength affects pressure — a stronger gravitational field increases the weight of the liquid above the object.

The Pressure in a Liquid Equation

  • Pressure in a liquid is calculated using the equation: P = hρg , where P is pressure in pascals (Pa), h is the depth in metres, ρ is the density in kg/m³, and g is the gravitational field strength in N/kg.
  • On Earth, the gravitational field strength is taken as g = 9.8 N/kg.
  • The equation shows that pressure increases proportionally with depth, density, and gravitational field strength.

Worked Example: Calculating Change in Pressure

  • At a depth of 20 m, the pressure is 20 × 1000 × 9.8 = 196,000 Pa.
  • At a depth of 90 m, the pressure is 90 × 1000 × 9.8 = 882,000 Pa.
  • The change in pressure is 882,000 − 196,000 = 686,000 Pa, which can also be found using the depth difference: 70 × 1000 × 9.8 = 686,000 Pa.

Understanding Upthrust

  • Upthrust is the resultant upward force exerted on a submerged object by the surrounding liquid.
  • Because the bottom of a submerged object is deeper than the top, the upward force on the bottom is greater than the downward force on the top, producing a net upward force.
  • All submerged objects experience upthrust, regardless of whether they float or sink.

Why Objects Float or Sink

  • Whether an object floats or sinks depends on the relative sizes of the upthrust (upward) and the object's weight (downward).
  • If the weight of the object is greater than the upthrust, the object sinks.
  • If the upthrust is greater than the weight of the object, the object floats.

Using Density to Predict Floating or Sinking

  • A simple rule is that if an object is denser than the liquid it is placed in, it will sink.
  • If an object is less dense than the liquid, it will float — for example, an apple floats in water because it is less dense than water.
  • Comparing the density of the object to the density of the liquid removes the need to calculate upthrust and weight separately.