Describe ways to increase the efficiency of an intended energy transfer.
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GCSE Physics Revision
Learn it. Recall it. Revise it.
GCSE Physics revision
Efficiency
Conservation and dissipation of energy
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AQA student objectives
Learning pathway
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Apply the scientific explanation of efficiency to a relevant example.
Analyse a new situation involving efficiency and explain the scientific reasoning.
Revision summary
Key knowledge
Read on screen, then print for Cornell-style active revision.
What is Efficiency?
- Efficiency describes the proportion of input energy that is converted into useful energy output by a device.
- Most devices are not 100% efficient because some energy is always transferred into an unwanted form, most commonly thermal energy.
- The energy that is not transferred into the intended useful form is called wasted energy or non-useful energy output.
Useful vs. Wasted Energy
- For a lamp, the input is electrical energy, which is split into light energy (useful) and heat energy (wasted).
- The purpose of the device determines which output is classed as useful โ for a lamp, only light energy counts as useful output.
- An electric heater is a special case where thermal energy is the intended output, so it is classed as useful rather than wasted.
The Efficiency Equation (Energy)
- useful energy output
- Efficiency can be calculated using the equation: efficiency = total energy input
- This equation gives efficiency as a decimal, which can be converted to a percentage by multiplying by 100.
- Efficiency values must always be between 0 and 1 (or 0% and 100%), as a value greater than 1 would imply more energy out than in, violating conservation of energy.
The Efficiency Equation (Power)
- When working with power rather than energy, efficiency is calculated as:
- efficiency = useful power output total power input
- Power-based efficiency calculations use the same decimal or percentage format as energy-based ones.
- To find useful power output, rearrange the equation to:
- useful power output = efficiency ร total power input
Worked Example: Comparing Lamps
- An incandescent bulb receiving 300 J and producing 45 J of light has an efficiency of 45
- 300
- = 0.15 (15%).
- 225
- An LED bulb receiving 300 J and producing 225 J of light has an efficiency of 300 = 0.75 (75%).
- 0.75
- The LED lamp is 0.15 = 5 times more efficient than the incandescent bulb.
Worked Example: Microwave Oven
- A microwave that is 70% efficient must first have its efficiency converted to a decimal:
- 70
- 100
- = 0.7
- With a total power input of 800 W, the useful power output is 0.7 ร 800 = 560 W.
Common Mistakes to Avoid
- A common error is inverting the efficiency fraction, dividing total input by useful output instead of the other way around.
- If your calculated efficiency is greater than 1 (or greater than 100%), this is a clear sign the division has been performed the wrong way around.
- The conservation of energy principle confirms that no device can have an efficiency above 100%, as energy cannot be created, only transferred.
Key Principles to Remember
- No device is perfectly 100% efficient, as all real devices lose some energy, most often as thermal energy.
- Efficiency is a ratio with no units, expressed either as a decimal between 0 and 1 or as a percentage between 0% and 100%.
- Always identify which energy or power output is classed as useful before substituting values into the efficiency equation.